排除if语句？

问题描述：

Is it somehow possible to exclude an if statement to two different files? When I write something like the following code, it gives a parse error: syntax error, unexpected end of file. Apparently, i always have to close an if statement in the same included file. Is there a way to accomplish what i want?

index.php:

<?php
require "top.inc.php"; // opening the if statement
  some code to execute if statement in top.inc.php is true
require "bottom.inc.php"; // closing the if statement
?>

top.inc.php:

<?php if (1 == 1) { ?>

bottom.inc.php:

<?php } ?>

以某种方式可以将if语句排除到两个不同的文件中吗？当我编写类似下面的代码时，它会给出一个解析错误：语法错误，意外的文件结尾 code>。显然，我总是要在同一个包含文件中关闭if语句。有没有办法实现我想要的？ p>

index.php： p>


 ＆lt;？php 
require“top.inc。  PHP的“;  //打开if语句
如果top.inc.php中的语句为true，则执行一些代码
require“bottom.inc.php”;  //关闭if语句
？＆gt; 
  code>  pre> 
 
  top.inc.php： p> 
 
 
 ＆lt;  ？php if（1 == 1）{？＆gt; 
  code>  pre> 
 
  bottom.inc.php： p> 
 
 
   ＆lt;？php}？＆gt; 
  code>  pre> 
  div>

答

No, it is not possible. Each .php file needs to have complete, valid syntax. includeing files is not exactly the same as copy-and-pasting their content.

答

<?
file_put_contents("temp.php",file_get_contents("top.inc.php"));
$Middle_Code = <<<HEREDOC
/*
Other code to be put inside this heredoc,
but, of course, outside this comment block!
*/
HEREDOC;
file_put_contents("temp.php",$Middle_Code,FILE_APPEND);
file_put_contents("temp.php",file_get_contents("bottom.inc.php"),FILE_APPEND);
require("temp.php");

答

You can't do that. What you can do would be the following

in your top.php

<?php if($condition) { 
           include "bottom.inc.php";    
?>

<?php } ?>

答

Each file will need to have correct syntax. The easiest way would be to define a variable to hold a value that is say 1 if the statement is true.

Something like:

top.php

if (1 == 1) $value = 1;

index.php

if ($value == 1) // do something

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