如何通过一个值到PHP阿贾克斯变量

问题描述：

这是我的javascript code：

this is my javascript code :

function  category(row){
    dataparam = "oper=delete&row="+row;
    $.ajax({
        type: "POST",
        url: "multiupload.php",
        data: dataparam,
        error:function() {
                alert("sorry")
        },
        success: function(html) {
            alert(html);
        }
    });
}

和我的PHP脚本：

$opers = (isset($_REQUEST['opers']) and $_REQUEST['opers'] != '' ) ? $_REQUEST['opers'] : '';
if($opers == "delete") {
        $row=$_REQUEST['row'];
        echo $row;
}

这是不工作...我不知道是什么问题。请帮我拿到了 $行变量在我的PHP脚本。

This is not working... I don't know what problem is. Please help me to get the $row variable in my php script.

答

它看起来像你有这个毛病， $ _ REQUEST ['OPERS'] 应该是 $ $ _ REQUEST ['OPER']

It looks like you have this wrong, $_REQUEST['opers'] it should be $_REQUEST['oper']

$opers = (isset($_REQUEST['oper']) and $_REQUEST['oper'] != '' ) ? $_REQUEST['oper'] : '';  

if($opers == "delete") {
    $row=$_REQUEST['row'];
    echo $row;
}

我也建议，当你期待的值来通过URL使用适当的超级全球是 $ _ GET 。有一个很小的机会，一个 $ _ COOKIE 可以拧你了。如果你使用它们，hapen给它OPER'的值。

I would also recommend that as you are expecting the values to come via URL you use the appropriate super global which is $_GET. There is a very small chance that a $_COOKIE could screw you over. If you use them and hapen to give it the value of 'oper'.

如何通过一个值到PHP阿贾克斯变量

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