根据匹配条件对SQL记录进行排序
问题描述：
我有这个查询:
SELECT * FROM table WHERE key LIKE '1,2,3,%' OR key LIKE '1,2,%' OR key LIKE '1,%'
是否可以根据首先匹配的条件对从此查询返回的记录进行排序.我想先获取所有与key LIKE '1,2,3,%'匹配的记录，然后与key LIKE '1,2,%'匹配，然后与其他记录匹配.
Is it posible to sort records returned from this query based on which conditions was matched first. I'd like to get all records that match key LIKE '1,2,3,%' first, then key LIKE '1,2,%' and the others after.
例如，如果我有以下记录:
For example, if I have these records:
key: "1,2,3,4"
key: "1,2,5"
key: "1,4"
key: "1,2,5,6"
key: "1,3"
key: "1,2,3,4,7"
key: "1,2,4"
我希望对它们进行排序:
I would like them to be sorted like so:
key: "1,2,3,4"
key: "1,2,3,4,7"
key: "1,2,4"
key: "1,2,5"
key: "1,2,5,6"
key: "1,3"
key: "1,4"
有可能吗?
答
.... ORDER BY CASE
WHEN key LIKE '1,2,3,%' THEN 1
WHEN key LIKE '1,2,%' THEN 2
ELSE 3
END
.... ORDER BY CASE
WHEN key LIKE '1,2,3,%' THEN 1
WHEN key LIKE '1,2,%' THEN 2
ELSE 3
END