检查用户名和密码的Andr​​oid

问题描述:

我有一个用户名和密码字段,现在我需要检查和重定向他在Android的下一个页面。

I have a username and password field and now i need to check and redirect him to the next page in Android.

    public void onCreate(Bundle savedInstanceState) {
         super.onCreate(savedInstanceState);   
         setContentView(R.layout.main);
         final EditText loginText = (EditText) findViewById(R.id.widget44);
         final EditText loginPassword = (EditText) findViewById(R.id.widget47);
         final Button button = (Button) findViewById(R.id.widget48);
            button.setOnClickListener(new View.OnClickListener() {
                public void onClick(View view) {
                 Intent myIntent = null;
                 if(loginText.getText().equals("admin") && 
loginPassword.getText().equals("admin")) {
                  System.out.println("Entering");
                  myIntent = new Intent(view.getContext(), Page1.class);
                 } else {

                 }
                 startActivity(myIntent);
                }
            });
        }

温度现在我通过硬编码值检查,但是这也并不为我工作。为什么?我通常检查的Java 这样的,为什么它不接受我的Andr​​oid同样的方式

Temp now i am checking by hardcoding the values, but this too does not work for me. Why? I usually check in Java like this, why does it not accept me the same way in Android

我想这是因为的EditText#的getText()返回编辑对象。尝试

I think it's because EditText#getText() returns an Editable object. Try

if(loginText.getText().toString().equals("admin") && 
    loginPassword.getText().toString().equals("admin")) {
    ...
}