简单汇编代码求解？该如何解决
简单汇编代码求解？？
t = offset->key[i].ib;
__asm
{
push eax
push ebx
movzx eax, word ptr[t]
mov ebx,s
mov [ebx], eax
pop eax
pop ebx
}
那段汇编代码啥意思呢？
------解决方案--------------------
*s = (int)offset->key[i].ib
------解决方案--------------------
貌似严格说应该是*s = (int)(unsigned short)offset->key[i].ib
*s = (int)(unsigned int)offset->key[i].ib
------解决方案--------------------
*s = (int)offset->key[i].ib
offset->key[i].ib 这个数是要比int要短的数，把他扩充到32为如讲一个unsi char强制转换为int，char强制转换为unsigned short，
t = offset->key[i].ib;
__asm
{
push eax
push ebx
movzx eax, word ptr[t]
mov ebx,s
mov [ebx], eax
pop eax
pop ebx
}
那段汇编代码啥意思呢？
------解决方案--------------------
*s = (int)offset->key[i].ib
------解决方案--------------------
貌似严格说应该是*s = (int)(unsigned short)offset->key[i].ib
*s = (int)(unsigned int)offset->key[i].ib
------解决方案--------------------
*s = (int)offset->key[i].ib
offset->key[i].ib 这个数是要比int要短的数，把他扩充到32为如讲一个unsi char强制转换为int，char强制转换为unsigned short，