php 之 查询 投票练习(0508)
练习题目:
解题:
方法一:
1. 投票主页面:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>投票</title> <style> #list { 400px; height:300px;} #jieguo { 400px; height:300px;} .x { float:left;} </style> </head> <body> <form action="TouChuLi.php" method="post"> <?php include ("DBDA.class.php"); $db=new DBDA(); //从调研题目表中找出题目代号和名称 $sql="select * from diaoyantimu limit 0,1"; $arr=$db->query($sql); $tmmc=$arr[0][1]; $tmdh=$arr[0][0]; echo "<div><h2>{$tmmc}:</h2></div>"; //从调研选项表中输出选项内容: $sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'"; $arrxx=$db->query($sqlxx); echo "<div id='list'>"; foreach ($arrxx as $v) { echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />"; } ?> <input type="submit" value="提交"> <input type="button" value="查看结果" > </form> </div> <div > <?php //计算总人数: $sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$tmdh}'"; $zrs=$db->query($sqlzs); foreach ($arrxx as $v) { $name=$v[1]; $number=$v[2]; if($zrs[0][0]==0) { $bfb = 0; } else { $bfb = ($number/$zrs[0][0])*100; } $bfb=round($bfb,2); echo "<div> <span class='x'>{$name} </span> <div class='x' style='200px; height:10px; background-color:#808080'> <div style='{$bfb}%; height:10px; background-color:#FF8040'> </div> </div> <span class='x'>{$number} </span> <span class='x'>{$bfb}% </span> </div> <br /> "; } ?> <input type="button" value="返回" > </div> <script> function Showjieguo() { document.getElementById("list").style.display="none"; document.getElementById("jieguo").style.display="block"; } function Showfanhui() { document.getElementById("list").style.display="block"; document.getElementById("jieguo").style.display="none"; } </script> </body> </html>
2.处理投票页面:
<?php $arr=$_POST["xx"]; include ("../DBDA.class.php"); $db=new DBDA(); foreach($arr as $v) { $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'"; $db->Query($sql,1);//1代表$sql的类型 } header ("location:TouPiao.php"); ?>
3. 建立访问数据库的类,封装用于引用:
<?php //执行一个sql语句,返回相应的结果 class DBDA { public $host="localhost";//数据库服务器地址 public $u;//数据库用户名 public $password="";//数据库密码 //执行SQL语句的方法 //参数里面:$sql代表要执行的sql语句;$type是sql语句的类型,0代表查询,1代表其他(增删改);$db代表要操作的数据库 function Query($sql,$type=0,$db="mydb") { //造连接对象 $dbconnect=new MySQLi($this->host,$this->uid,$this->password,$db); //判断连接是否出错 !mysqli_connect_error() or die("连接失败!"); //执行sql语句 $result=$dbconnect->query($sql); //判断SQL语句类型 if($type==0) { //如果是查询语句返回结果集的二维数组 return $result->fetch_all(); } else { //如果是其他语句,返回true或false return $result; } } }
方法二:
1. 投票主页面:
<html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>投票</title> <style> .x { float:left;} </style> </head> <body> <form action="TouChuLi.php" method="post"> <?php include ("../DBDA.class.php"); $db=new DBDA(); //从调研题目表中找出题目代号和名称 $sql="select * from diaoyantimu limit 0,1"; $arr=$db->query($sql); $tmmc=$arr[0][1]; $tmdh=$arr[0][0]; echo "<div><h2>{$tmmc}:</h2></div>"; //从调研选项表中输出选项内容: $sqlxx="select * from diaoyanxuanxiang where timudaihao='{$tmdh}'"; $arrxx=$db->query($sqlxx); echo "<div id='list'>"; foreach ($arrxx as $v) { echo "<div><input type='checkbox' value='{$v[0]}' name='xx[]'>{$v[1]}</div><br />"; } ?> <input type="submit" value="提交"> <a href="ChaKan.php"><input type="button" value="查看结果" ></a> </form> </body> </html>
2. 处理投票页面:
<?php $arr=$_POST["xx"]; include ("../DBDA.class.php"); $db=new DBDA(); foreach($arr as $v) { $sql = "update diaoyanxuanxiang set numbers = numbers+1 where ids = '{$v}'"; $db->Query($sql,1);//1代表$sql的类型 } header ("location:TouPiao.php"); ?>
3. 查看投票结果页面:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>查看结果</title> <style> .x { float:left;} </style> </head> <body> <?php include ("../DBDA.class.php"); $db=new DBDA(); //从调研题目表中找出题目代号和名称 $sql="select * from diaoyantimu limit 0,1"; $arr=$db->query($sql); $tmmc=$arr[0][1]; echo "<div><h2>{$tmmc}:</h2></div>"; //从调研选项表中输出选项内容: $sqlxx="select * from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'"; $arrxx=$db->query($sqlxx); //计算总人数: $sqlzs="select sum(numbers) from diaoyanxuanxiang where timudaihao='{$arr[0][0]}'"; $zrs=$db->query($sqlzs); foreach ($arrxx as $v) { $name=$v[1];//调研项目名称 $number=$v[2];//选择该项的人数 //判断总人数是否为0 if($zrs[0][0]==0) { $bfb = 0; } else { $bfb = ($number/$zrs[0][0])*100;//求百分比 } $bfb=round($bfb,2); //取小数点后两位 echo "<div> <span class='x'>{$name} </span> <div class='x' style='200px; height:10px; background-color:#808080'> <div style='{$bfb}%; height:10px; background-color:#FF8040'> </div> </div> <span class='x'>{$number} </span> <span class='x'>{$bfb}%</span><br /> </div><br />"; } ?> <br /> <a href="TouPiao.php"><input type="button" value="返回"></a> </body> </html>
网页显示结果: