txt文件读取后，数据如何避免的有关问题

txt文件读取后，数据如何处理的问题
[code=C/C++][/code]
string filename;
cout << "Please enter the file name: ";
cin >> filename;
//cin.clear();

ifstream infile;
if(!open_file(infile,filename))
{
cerr << "No input file!" << endl;
return 1;
}
string line;
while(getline(infile, line))
{
cout<<line;
}
上述代码读取file.txt中的十六位数字：
0xEA6D, 0xEBF0, 0xED40, 0xEE5C, 0xEF62, 0xF04B, 0xF11C, 0xF1D9, 0xF284, 0xF31F, // 10
0xF3AD, 0xF430, 0xF4A8, 0xF517, 0xF57E, 0xF5DD, 0xF636, 0xF68A, 0xF6DA, 0xF723, // 20
0xF768, 0xF7A8, 0xF7E7, 0xF821, 0xF857, 0xF88A, 0xF8BD, 0xF8EC, 0xF918, 0xF942, // 30
用line一次读取一行，如何去除掉最后的"//10"，然后再将十六进制转化成十进制存储，谢谢！

------解决方案--------------------

C/C++ code

#include "stdafx.h"

#include <iostream>
#include <fstream>
#include <string>
#include <vector>
using namespace std;

int main(int argc, char* argv[])
{
    string filename;  
    cout << "Please enter the file name: ";  
    cin >> filename;  
    
    ifstream file(filename.c_str(), ios::in);

    string line;
    vector<int> vec;
    char seps[] = ", ";
    char* token = NULL;
    while(getline(file, line))
    {
        char* buf = new char[line.length() + 1];
        strcpy(buf, line.c_str());

        char* p = buf;
        token = strtok(p, seps);
        while(NULL != token)
        {
            if(token == strstr(token, "0x"))
            {
                cout<<strtoul(token, NULL, 16)<<endl;
                vec.push_back(strtoul(token, NULL, 16));
            }
            token = strtok(NULL, seps);
        }
        delete[] buf;
        buf = NULL;
    }

    return 0;
}

txt文件读取后，数据如何避免的有关问题

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