Leetcode 559. Maximum Depth of N-ary Tree

c++，如果本节点为空，返回0，否则返回这棵树孩子中（找到每个节点的最大值，返回最大值+1即可，1是本节点的深度）

/*
// Definition for a Node.
class Node {
public:
    int val;
    vector<Node*> children;

    Node() {}

    Node(int _val) {
        val = _val;
    }

    Node(int _val, vector<Node*> _children) {
        val = _val;
        children = _children;
    }
};
*/
class Solution {
public:
    int maxDepth(Node* root) {
        if(!root) return 0;
        int ans = 0;
        for(int i = 0; i < root->children.size(); i++)
            ans = max(ans, maxDepth(root->children[i]));
        return ans + 1;
    }
};

Leetcode 559. Maximum Depth of N-ary Tree

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