考虑到语言环境日期格式，将DateTime对象转换为字符串

问题描述：

Is there a way in PHP to get a string from a DateTime object considering the date format according to the locale configuration without having an array of countries => formats ?

$dt = DateTime::createFromFormat(DateTime::ISO8601, '2016-07-27T19:30:00Z');

$ $usadt = /* What PHP function here? */
$ $brazildt = /* What PHP function here? */

echo ("USA Format: " . $usadt);
echo ("Brazil Format: " . $brazildt);

USA Format: 2016/07/27 07:30pm
Brazil Format: 27/07/2016 19:30

考虑到日期，PHP中是否有办法从DateTime code>对象获取字符串根据区域设置配置格式化而不具有 countries =＆gt;的数组格式 code>？ p>

  $ dt = DateTime :: createFromFormat（DateTime :: ISO8601，'2016-07-27T19：30：00Z'）; 
 
  $ $ usadt = / *这里有什么PHP功能？  * / 
 $ $ brazildt = / *这里有什么PHP功能？  * / 
 
echo（“美国格式：”。$ usadt）; 
echo（“巴西格式：”。$ brazildt）; 
 
USA格式：2016/07/27 07:30 pm 
Brazil格式：27 /  07/2016 19:30 
  code>  pre> 
  div>

答

In the strftime() php manual it says

Format the time and/or date according to locale settings. Month and weekday names and other language-dependent strings respect the current locale set with setlocale().

So take a look at setlocale() and change it before using formatted date.

how to format for your datetime locale

%x Preferred date representation based on locale, without the time

%X Preferred time representation based on locale, without the date

example

$dt = DateTime::createFromFormat(DateTime::ISO8601, '2016-07-27T19:30:00Z');
setlocale(LC_TIME, 'en_US');
$usadt = strftime('%x %X', $dt->getTimestamp());
setlocale(LC_TIME, 'pt_BR.UTF-8');
$brazildt = strftime('%x %X', $dt->getTimestamp());
echo "USA Format: $usadt<br>";
echo "Brazil Format: $brazildt<br>";

outputs

USA Format: 07/27/2016 12:30:00 PM

Brazil Format: 27-07-2016 12:30:00

note

I got the locales from this page;

考虑到语言环境日期格式，将DateTime对象转换为字符串

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